Subqueries: SELECT (SELECT ...), (SELECT ...) FROM ... If they don't work, upgrade to a newer version of MariaDB. (If this is the customer I assume it is, use RackSpace's IUS repo to upgrade). Alternately, create two VIEWs, one for each aggregate count, and OUTER JOIN them. -Adam On March 24, 2016 9:16:31 AM CDT, Trevor Cordes <trevor@tecnopolis.ca> wrote:
Can anyone help me figure out how to do this in SQL (MySQL)?
(pseudo-code giving you the gist):
SELECT custid, (count orders where ttl=X), (count orders where ttl=Y) FROM ordertable GROUP BY custid;
I basically want to count two different things based on two different wheres. If I put in a where clause then I select either the X or the Y
but I can't seem to get both in such a way I can count the X's and Y's. I tried thinking about unions but couldn't make it work. I want to do this all in 1 query as I want the sorted union of all custid's (X and Y).
P.S. ordertable has/can have multiple entries for each custid.
Ideas are appreciated! _______________________________________________ Roundtable mailing list Roundtable@muug.mb.ca http://www.muug.mb.ca/mailman/listinfo/roundtable
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